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First I'll answer the quoting question. Try the following snippet.
In the case of $text, we used " (double quotes) and thus, \n was expanded to mean a newline. In the case of $var, we used single quotes, and \n remained the literal characters \ and n. Now try this code:
In the case of the first print statement, the variable $text is interpolated within the string (its value is put into the string). In the case of the second print statement, $text is the literal text printed. Now for =>. => is sometimes called the "fat comma". It's most common use is in declaring elements of a hash, as in:
The fat comma also has the effect of 'single quoting' the text immediately to its left. So the above snippet is equal to:
Now for ->. That is used for dereferencing, which is an entirely different subject, having nothing to do with the => fat comma. If $aref is a reference to an array, one of the notations you can use to dereference that ref, and grab a single element is to use the dereference operator ->, like this: $aref->[3]. That's the same as: ${$aref}[3], and a lot less ambiguous than something like $$aref[3]. As Zaxo has stated, you should have a look at perlsyn, perlop, and perlreftut. Dave In reply to Re: deference and inreference operators
by davido
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