Uhm... $! and $? do not act differently with sudo thrown in the mix. The only real difference is that you are executing a different command (i.e. sudo rather than the command that sudo is executing.)
$> perl sudotest.pl
Password:
sudo: /foo/bar/paco: command not found
$ sudo /foo/bar/paco
ERRNO =
CHILD_ERROR = 256
In that case, sudo executed just fine and returned a 1 (which is what sudo does when the command it is given can't be executed.) Remember to shift $?. (256 >> 8 == 1)
Can't exec "/foo/bar/paco": No such file or directory at sudotest.pl l
+ine 8.
$ /foo/bar/paco
ERRNO = No such file or directory
CHILD_ERROR = -1
Use of uninitialized value in print at sudotest.pl line 12.
Again, normal behavior. Perl can't execute the command given so it sets $? to -1 and returns the reason in $! (as documented.)
$ ls -laF
ERRNO = Illegal seek
CHILD_ERROR = 0
total 138
drwxrwxrwx 5 ignatz paco 1024 Jan 16 15:16 ./
drwxr-xr-x 21 ignatz paco 1536 Jan 16 15:34 ../
drwxrwxrwx 2 ignatz paco 512 Dec 18 15:30 CVS/
-rw-r--r-- 1 ignatz paco 298 Jan 16 14:44 sudotest.pl
Once again, this behaved as expected. The command executed successfully, so $? contains 0. In this case, $! is not relevant.
Keep in mind that $! is only meaningful in association with backticks and system when $? == -1.
-sauoq
"My two cents aren't worth a dime.";
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