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You are slightly wrong: <code$qr = qr/./; $qr =~ m/$qr/; $qr =~ $qr;</code> is exactly identical. Again, some opcode info to illuminate. It also yields the slightly interesting form $text = 'abcd'; $text =~ qr/./ but then... maybe that's not quite normal ;-)

i <@> leave[t1] vKP/REFC ->(end) 1 <0> enter ->2 2 <;> nextstate(main 5 v ->3 5 <2> sassign vKS/2 ->6 3 </> qr(/./) s ->4 - <1> ex-rv2sv sKRM*/1 ->5 4 <> gvsv s ->5 6 <;> nextstate(main 5 v ->7 >> Here you see the $qr =~ m/$qr/ form b </> match() vKS ->c - <1> ex-rv2sv sK/1 ->8 7 <> gvsv s ->8 a <|> regcomp(other->b) sK/1 ->b 8 <1> regcreset sK/1 ->9 - <1> ex-rv2sv sK/1 ->a 9 <> gvsv s ->a >> And here you see the $qr =~ $qr form c <;> nextstate(main 5 v ->d h </> match() vKS ->i - <1> ex-rv2sv sK/1 ->e d <> gvsv s ->e g <|> regcomp(other->h) sK/1 ->h e <1> regcreset sK/1 ->f - <1> ex-rv2sv sK/1 ->g f <> gvsv s ->g
__SIG__ use B; printf "You are here %08x\n", unpack "L!", unpack "P4", pack "L!", B::svref_2object(sub{})->OUTSIDE;

In reply to Re^6: meaning of /o in regexes by diotalevi
in thread meaning of /o in regexes by mce

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