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A little afternoon golf produced this scary looking solution... It assumes the elements in the array are unique (i.e. a set) and none of them contain the comma character.
#!/usr/bin/perl -wT use strict; my @a = 1..5; my $l = 3; local $" = ','; my @combos = grep!$;{"@$_"}++,map[sortsplit','], grep!/([^,]+).*,\1,/,glob"{@a},"x$l; print "@$_\n" for @combos; __END__ 1,2,3 1,2,4 1,2,5 1,3,4 1,3,5 1,4,5 2,3,4 2,3,5 2,4,5 3,4,5
Update: There is a subtle bug in the second line of the golfed statement... grep!/([^,]+).*,\1,/ is supposed to filter out all permutations that have doubled elements, but its a bit faulty. It doesn't affect the final value of @combos though. Anyone want to take a guess at it? Whats the bug, and why doesn't it matter in the end?

-Blake


In reply to Re: Combinatorics by blakem
in thread Combinatorics by ezekiel

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