slightly cheating ;-)
DB<33> x @a=(0,1,1); grep { (each @a)[1] } A..L
0 'B'
1 'C'
2 'F'
3 'G'
4 'J'
5 'K'
here the general case w/o cheating:
(like when the filter cycle ends with a 1 you'd need)
DB<34> x @a=(0,0,1,1); grep { (each @a)[1] // (each @a)[1] } A..L
0 'C'
1 'D'
2 'G'
3 'H'
4 'K'
5 'L'
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