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The right hand side of s/// does not execute code unless you use the "e" modifier. Would you bet your money on that statement? I would not. You are right, s/// usually does not execute code without the /e modifier. But Perl would not be Perl if you could not mess around with that. Note that even if you could mess with perl, you probably should not. I'll abuse a trick invented by Andrew Pimlott, that I saw first in the "Perl hardware store" talks (1, 2, 3, 4) by Dominus:
But there is also a way without tie magic. Dereferencing an anonymous array reference:
Both tricks (ab)use the fact that s/// interpolates the replacement expression, unless you force it not to do so (using ' as the delimiter instead of /). Alexander
-- Today I will gladly share my knowledge and experience, for there are no sweeter words than "I told you so". ;-) In reply to Re^2: Using SprintF in S & R
by afoken
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