Hello punitpawar,

I am trying to write a program that will create a binary tree for any 10 random numbers that are generated.

From your later posts, it appears that you actually want a sorted binary tree. has various modules you can use for this. Here is one example:

#! perl
use strict;
use warnings;
use Tree::Binary::Search;
use Tree::Binary::Visitor::InOrderTraversal;

for (1 .. 20)
{
    my $btree = Tree::Binary::Search->new;
       $btree->useNumericComparison;

    for (1 .. 10)
    {
        my $num = int rand 100;
        redo if $btree->exists($num);
        $btree->insert($num => 1);
    }

    my $visitor = Tree::Binary::Visitor::InOrderTraversal->new;
       $visitor->setNodeFilter(sub { $_[0]->getNodeKey });

    $btree->accept($visitor);
    print join(' ', map { sprintf '%2d', $_ } $visitor->getResults), "
+\n";
    $btree->DESTROY;
}
[download]

Output:

13:09 >perl 1475_SoPW.pl
 0  9 14 33 37 55 60 77 89 99
15 26 28 51 59 75 78 79 94 99
18 31 33 38 44 47 70 73 77 84
 4 21 24 28 38 57 65 76 98 99
16 42 50 62 70 71 83 87 92 94
21 29 35 40 49 68 71 79 85 90
 2  5 11 16 24 46 50 55 75 99
19 26 28 39 42 51 53 59 66 98
26 35 41 45 53 54 67 81 88 95
19 28 45 51 58 64 65 67 79 82
 0 21 27 54 60 63 64 73 78 99
 0  5 13 27 31 50 61 74 77 92
11 13 14 29 52 60 71 79 80 86
 8  9 29 36 37 50 58 69 81 82
10 14 23 38 46 53 57 67 90 97
 7  8 13 14 30 32 34 41 50 76
 6 11 21 28 50 53 78 79 96 98
19 24 28 37 60 71 78 85 88 93
14 26 28 31 42 59 71 83 87 94
 0  8 13 15 19 51 52 71 78 85

13:09 >
[download]

As you can see, in-order traversal outputs the numbers in sorted (numerical ascending) order, showing that the underlying binary tree is sorted.

Hope that helps,