maybe
DB<20> print join " ", reverse split /(..)/ , sprintf "%06x\n", 2*10*
+*$_ for 0..5
02 00 00
14 00 00
c8 00 00
d0 07 00
20 4e 00
40 0d 03
DB<21>
I'm not sure why you want low bytes first, but please note you had trailing 00s in your example too.
update
this will give you the number of necessary bytes
DB<29> say 1+int (log (2*10**$_)/log 256) for 0..5
1
1
1
2
2
3
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