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I have problems understanding the doc.
If "running out of memory is untrappable" how can I be able to run code anyway? Or is it still trappable via $SIG{__DIE__} ? In that case why can't I just pre-allocate variables in the sig-handler's closure instead of requesting more memory? Why $^M at all? Honestly I don't know how to simulate "running out of memory" for experimenting.
Cheers Rolf In reply to Re^2: How use $^M?
by LanX
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