comment on

> That seems to be because a reference to a literal actually constructs a new scalar;

again more theories ...

see how the ref to a real constant like a stays stable in Re^8: Shouldn't references be readonly? (updated) and please explain the difference to your allegedly constant 1 .

> There is no such thing as a literal aggregate in Perl — the {} and [] operators are defined as constructors instead.

Defined? ... Source?

Cheers Rolf
_{(addicted to the Perl Programming Language :)

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