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oct , perlquote,, perlnumber, octal
$ perl -le " print 041 " 33 $ perl -le " print chr 041 " ! $ perl -le " print chr 33 " ! $ perl -le " print ord q{!} " 33

So the integer 33 is written in octal as 041, and if you chr 33 you get !

Make sense?

In a double quoted string 041 is 041, but \041 is chr 33 (octal escape)

$ perl -le " print qq{041} " 041 $ perl -le " print qq{\041} " !

In reply to Re: syntax of Data::Dump (perlquote oct octal escape perlrebackslash) by Anonymous Monk
in thread syntax of Data::Dump by WoodyWeaver

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