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how to exit the loop after complete 3 rounds...?? it means... if you enter 3 times wrong input it should exit from the program... here i am providing code please modify it
#!/user/bin/perl print"enter the rang of array:\n"; chomp($c=<STDIN>); while($i=1){ print"while loop round:$i\n"; if($i>3){ exit; } if($c =~ /^\[|[a-z,A-Z]+/){ print "it is invalid please enter digits\n"; #print"enter the rang of array:\n"; #chomp($c=<STDIN>); } elsif($c =~ /^[1-9]+/){ print "you are entered correct input\n"; last; } $i++; } @a=(); $b; $1; print"Enter the array:\n"; for($i=0;$i<$c;$i++){ chomp($b=<STDIN>); $a[$i]=$b; } #for($i=0;$i<@a;$i++){ #print"the array $a[$i]\n"; #} #print"the PSI ID's:"; foreach $val(@a){ #print"####$val###\n"; if($val=~ /^([a-z]+)\s?PSI\-ID\-?(\d+)/){ print"value=$2\n"; push(@b,$1); push(@c,$2); } } print"the pax id's with PSI:\n"; for($i=0;$i<=@b;$i++){ for($j=0;$j<=@c;$j++){ if($i==$j){ print"$b[$i] $c[$j]\n"; } } }

In reply to Re^2: Regex shows only last match multiple times? by Anonymous Monk
in thread Regex shows only last match multiple times? by GertMT

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