Because it's valid code, $two could be a boolean to be tested and as a side-effect $one is set.
try
perl -e 'use strict; use warnings; my $one = 1; if( $one = 2 ) { prin
+t "True\n"; } else { print "False\n"; } '
Found = in conditional, should be == at -e line 1.
True
or
perl -we '$a=1; print (($a = 2) ? "True" : "False");'
Found = in conditional, should be == at -e line 1.
cause now it makes less sense.
YMMV!
UPDATE
And personally I would be glad if this would cause a warning, too!
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