in reply to Re: Mini-Tutorial: Dereferencing Syntax
in thread Mini-Tutorial: Dereferencing Syntax
$$foo is not a shorthand for $foo->.
>perl -E"$foo=\'foo'; say $$foo;" foo >perl -E"$foo=\'foo'; say $foo->;" syntax error at -e line 1, near "->;" Execution of -e aborted due to compilation errors.
You're probably thinking of the equivalency of $$foo[...] and $foo->[...] and of $$foo{...} and $foo->{...}, but that's already mentioned.
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