Re: arrays: shifting in while loop

My understanding is that the while will execute so long as there are elements in @a...

ivanthemad: I expect you already understand the following point perfectly well, but I want to dispell my sneaking suspicion of a possible misapprehension on your part.

The while-loop in the example code will only begin execution (Update: of ~~a loop~~the loop body) if the array is non-empty. However, (Update: once begun) ~~loop~~loop body execution will continue regardless of the state of the array unless an explicit loop exit is made conditional upon array state, e.g., with a statement like last unless @a;.

Update: Clarified (hopefully) pertinence to loop body per repellent.

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Re^2: arrays: shifting in while loop by repellent (Priest) on Mar 07, 2012 at 05:01 UTC
... loop execution will continue* regardless of the state of the array unless an explicit loop exit is made ...* Hmm, really? I always thought the while-loop EXPR was re-evaluated after each iteration: `my @a = (3, 4); while (do { say "yo"; @a }) { say "hi mom"; shift @a; # no explicit loop break out } say "bye mom"; __END__ yo hi mom yo hi mom yo bye mom` [download]	[reply] [d/l]
Re^3: arrays: shifting in while loop by AnomalousMonk (Archbishop) on Mar 07, 2012 at 15:17 UTC
... the while-loop EXPR [is] re-evaluated after each iteration... It is, but I was trying to make a (perhaps rather trivial) point with regard to continued execution of the loop body (which I've tried to clarify in the original reply) as exemplified below. `>perl -wMstrict -le "my @ra = (9, 8, 7); ;; while (@ra) { print 0+@ra, ' in @ra'; shift @ra; print 0+@ra, ' in @ra'; shift @ra; print 0+@ra, ' in @ra'; shift @ra; print 0+@ra, ' in @ra'; shift @ra; print 0+@ra, ' in @ra'; shift @ra; print 0+@ra, ' in @ra'; } " 3 in @ra 2 in @ra 1 in @ra 0 in @ra 0 in @ra 0 in @ra` [download]	[reply] [d/l]
Re^4: arrays: shifting in while loop by repellent (Priest) on Mar 07, 2012 at 17:07 UTC
Great, I knew I missed something from your original post.	[reply]


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