Re^3: How to call Linux command sequentially

When you call exec a new process is forked and the parent quits, whereas when you call system the parent waits for the system call to complete. Using backticks `` or the qx is similar to a system call but the output is returned to the caller. eg.

$ perl -Mstrict -e 'my @out =qx{ls $ENV{HOME}/tmp}; 
chomp @out;
print join (", " , @out), "\n";'
a.out, test.c, test.dat, test.pl
[download]

Could you show us how you call the command within your Perl script?

print "Good ",qw(night morning afternoon evening)[(localtime)[2]/6]," fellow monks."

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Re^4: How to call Linux command sequentially by mv.ashwin@gmail.com (Novice) on Sep 13, 2011 at 09:22 UTC
OK there was syntax problem i was able to run the command. But here comes another problem. The first command here creates the an environment, in that environment i need to execute the second command. Here nither system nor exec will do these. Untill I manually exit from environment the second command is not running. Once i exit from environment the second executes. But i need the second command to be executed in environment which was set by first command. Is it possible to do so? Please help!!!!	[reply]
Re^5: How to call Linux command sequentially by Corion (Patriarch) on Sep 13, 2011 at 09:25 UTC
See Get default login environment.	[reply]
Re^5: How to call Linux command sequentially by graff (Chancellor) on Sep 13, 2011 at 09:33 UTC
You could try something like: `#!/usr/bin/perl use strict; my $shpid = open( SH, '\|-', '/bin/bash' ) or die "Can't launch bash: $ +!\n"; my @command_list = ( "first_command args ...\n", "second_command args ...\n" ... ); for my $cmd ( @command_list ) { print SH $cmd; } print SH "exit\n"; waitpid( $shpid, 0 );` [download] If the list of commands actually includes things that change the shell environment for subsequent commands, that should work as intended.	[reply] [d/l]


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