Re^2: perl -i -pe ... with eof() testing

This is what I figured, too (kind of). But why does it then "work" with the eof form? This produces

--- cat before ---
line1
line2
line3
line1
line2
line3
--- script output to stdout ---
--- cat after ---
line1
line2
line3
opt=bar
line1
line2
line3
opt=bar
[download]

(I say "work" in quotes because it's not what is needed here, but what I would've expected.)

Also, perl -MO=Deparse ... doesn't highlight any difference, except the eof vs. eof() itself.

Comment on Re^2: perl -i -pe ... with eof() testing Select or Download Code

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Re^3: perl -i -pe ... with eof() testing by ikegami (Patriarch) on Feb 08, 2011 at 20:05 UTC
The only way `(eof)` can check for per-file eof as documented would be if it read from the real file handle instead of the magical handle. The magical handle doesn't move to the next file because it's not used.	[reply] [d/l]
Re^4: perl -i -pe ... with eof() testing by Anonyrnous Monk (Hermit) on Feb 08, 2011 at 20:38 UTC
Thanks, you're right. Just for the record: I had confused myself unnecessarily by not putting a separator in between the `cat` of file1 and file2. Which made me wonder why the magical file handle is only being advanced by `eof()` at the very end, and not at every file boundary. When you do it properly, however, i.e. something like `cat file1 echo --- cat file2` [download] the output is `... --- perl output to stdout --- line3 opt=bar --- cat after --- line1 line2 --- line3 line1 line2` [download] which shows that line3 of the first file does in fact belong to file2 after the processing... P.S. I've now settled on suggesting my collegue `perl -i -pe '$f\|\|=s/opt=.*/opt=bar/; $_.="opt=bar\n" if !$f && !@ARGV +&& eof' files...` [download] (but unfortunately it took a little too long to get working to leave an "it's easy with Perl" impression — that's my fault, however :)	[reply] [d/l] [select]


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