Re^2: Adding the duplicate data using arrays

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Comment on Re^2: Adding the duplicate data using arrays

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Re^3: Adding the duplicate data using arrays by space_agent (Acolyte) on Aug 11, 2010 at 11:44 UTC
Just to sum it up. Here (.) takes both columns as is a greedy quantifier and takes as much as possible and this is until the number (\d+) comes into play. `while (<DATA>) { m/(.*)\s+(\d+)/; $hash{$1} += $2; #$1 is the fruit $2 the number } for my $fruit (keys %hash) { print "$fruit $hash{$fruit}\n"; } __END__ Apple Grape 100 Ginger Fry 200 Apple Grape 80 Ginger Banana 800 Ginger Fry 150 Ginger Banana 45` [download]	[reply] [d/l]
Re^3: Adding the duplicate data using arrays by JavaFan (Canon) on Aug 11, 2010 at 09:14 UTC
Ah, but you don't really have three columns. You just have two columns, with the first column being "Apple Banana", etc.	[reply]
Re^4: Adding the duplicate data using arrays by changma_ha (Sexton) on Aug 11, 2010 at 10:07 UTC
Ok..JavaFan. If i have the data "Apple banana 100" if i split on the basis of "\s+" it will split Apple and Banana...so how can i split in such a way that "Apple Banana " is the key and "100" is the value...give me some wisdom	[reply]
Re^5: Adding the duplicate data using arrays by JavaFan (Canon) on Aug 11, 2010 at 10:48 UTC
`my ($fruit, $value) = "Apple banana 100" =~ /^(.*\S)\s+([0-9]+)/;` [download]	[reply] [d/l]