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Re: Finding all connected nodes in an all-against-all comparison

by LanX (Sage)
on May 07, 2010 at 14:52 UTC ( #838921=note: print w/replies, xml ) Need Help??


in reply to Finding all connected nodes in an all-against-all comparison

So which solution do you expect with this data?
A C B C

There is no path from A to B, so do you consider them in the same or different groups?

Or do you have a guaranty that these intersections are not possible?

Cheers Rolf

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