Re^3: Regex fun

I didn't say you couldn't build regexps dynamically. I said the quantifier can't be variable. Perl regular expressions don't even have variables, so you couldn't possibly have shown one being used.

You can't have a quantifier until you have a regexp, and you don't have a regexp until you interpolate anything that needs to be interpolated.

What's the quantifier in the following?

$ perl -E 'my $x = "2"; "ab" =~ /.{$x}/ and say "Matched"'
Matched
[download]

Are you saying it's different in this one?

$ perl -E 'my $x = "{2}"; "ab" =~ /.$x/ and say "Matched"'
Matched
[download]

What about this one?

$ perl -E 'my $x = "2}"; "ab" =~ /.{$x/ and say "Matched"'
Matched
[download]

In all cases, the quantifier is {2}. No variables is involved. Sure, the regexp is produced from a variable, but that has nothing to do with the quantifier.

Update: Clarified.

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Re^4: Regex fun by JadeNB (Chaplain) on Dec 15, 2009 at 21:59 UTC
Perl regular expressions don't even have variables, so you couldn't possibly have shown one being used. This is what I first thought you meant, but it didn't make any sense to me. If one distinguishes “regex variables” (variable at regex run-time) from “Perl variables” (constant at each regex run-time ^), then, as you (basically) say, the only ones (I think) are the `\1` back-references; but, when Hena said I would assume that quantifier cannot be a '\x' variable you said It's simpler than that: The quantifier cannot be variable. The only reason I could think of to make this comment is if there were some other sort of variable, but you seem to be saying that there isn't. Did I misunderstand? UPDATE: ^ False, as I finally realised in Re^6: Regex fun.	[reply] [d/l]
Re^5: Regex fun by ikegami (Patriarch) on Dec 15, 2009 at 22:22 UTC
The only reason I could think of to make this comment is if there were some other sort of variable Or if someone posts an SoPW asking how to make it variable. Actually, it was to say that there wasn't "some other sort of variable". The OP's supposition implied that variables could be used there. They can't. That's what I said. Aside from that, did you forget about capture buffers, the return value of the last `(?{ })` and Perl variables? There's just no way to access them there. Update: Added second and third para.	[reply] [d/l]
Re^6: Regex fun by JadeNB (Chaplain) on Dec 15, 2009 at 22:55 UTC
Thanks for the additional paragraphs. The OP's supposition implied that variables could be used there. They can't. That's what I said. That's not how I read I would assume that quantifier cannot be a '\x' variable at all—it seems to me specifically to be saying that you can't use a variable there. Do you mean that, since it mentions that you can't use one sort of variable, it implies that you can use others? Aside from that, did you forget about capture buffers, the return value of the last `(?{ })` and Perl variables? There's just no way to access them there. You certainly can use, at least in the sense of referring to, capture buffers (which I guess means `$1` instead of `\1`?) and Perl variables, like `/(.{$1}){$a}/`; since their values don't change during the regex match ^, the result is the same (as you pointed out) as substituting in their values before running the regex. (Indeed, I think that's exactly what happens internally.) This is just what I meant in Re: Regex fun; so, as I indicated there, I must (still) be misunderstanding you. UPDATE: To avoid the appearance of slyly avoiding the bit about the return value of the last `(?{ })`, I didn't forget about it, but only because I never knew about it. Thanks! Another UPDATE: ^ Ah, this is probably a crucial point! I always assumed that `$1` didn't change until the match had completed; but I guess it's more accurate to say that it does change, but that all the interpolation has already happened at that point, so that change is not reflected in the regex. There's my misunderstanding; sorry!	[reply] [d/l] [select]
Re^7: Regex fun by ikegami (Patriarch) on Dec 16, 2009 at 00:55 UTC


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