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Re: Data Structure Question

by kyle (Abbot)
on Nov 25, 2009 at 21:52 UTC ( #809442=note: print w/replies, xml ) Need Help??

in reply to Data Structure Question

One way to handle this would be to put your data into a database and query it out. That can be useful especially if you have many many records or you have a data set that grows over time, and you don't want to build it repeatedly.

I'd probably represent your data with an array of hashes.

my @records = ( { employee => 10001, form => 10, date => 20090101, }, { employee => 10002, form => 10, date => 20080515, }, { employee => 10003, form => 10, date => 20080323, }, );

What's nice about this is that each hash can expand to have more fields as necessary. When you want to summarize by any given field, you can do this:

sub summarize_by { my $field_name = shift @_; my %out; for my $r ( @records ) { push @{ $out{$r->{$field_name}} }, $r; } return \%out; }

What you'd get from that is a hash of arrays of hashes. Each key of the top level hash is a unique value of the field you specified, and that hash's values are references to an array of records that had that key-value combination.

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