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Capturing input from pipe?

by Zombie lowlife (Initiate)
on Apr 27, 2001 at 18:25 UTC ( #76108=categorized question: print w/replies, xml ) Need Help??
Contributed by Zombie lowlife on Apr 27, 2001 at 18:25 UTC
Q&A  > input and output


I want to write a script which captures input from a pipe.
e.g. user@host:/#echo "bla" |
I know I can't capture the input with $ARGV in this case, can anybody tell me how I can do this?

Answer: Capturing input from pipe?
contributed by tomhukins

A pipe passes the output of one command to the input of another. So, to read the output of your echo command, read from STDIN. An example might be:

#!/usr/bin/perl print <>;
Answer: Capturing input from pipe?
contributed by ariels

Alternatively, if you really do just want to read standard input, you can read the predefined filehandle STDIN. For instance, to add line numbers to all lines coming from your pipe, you could do this:

#!/usr/local/bin/perl -w use strict; while (<STDIN>) { print "$. $_" }

But almost any program is more useful if it can read either STDIN or filenames supplied on the command line. So reading <> almost always makes more sense.

Answer: Capturing input from pipe?
contributed by hdp

Oft-used command line switches related to this subject are -p, -n, and -a (especially in conjunction with -F). See perlrun for how they work and what they do.


Answer: Capturing input from pipe?
contributed by Zombie lowlife

Okeeee, that was ALLOT simpler then I thought but it works exactly like I want, thanks allot.

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