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How do I convert a very long bit string into a number?

by jdporter (Paladin)
on Jan 15, 2009 at 21:42 UTC ( [id://736683]=perlquestion: print w/replies, xml ) Need Help??

jdporter has asked for the wisdom of the Perl Monks concerning the following question: (math)

I'm calling a function from a third-party module which advertises as returning a very long bit string. I want to use this value as a true perl number, e.g. to do math on it. How can I do that?

Originally posted as a Categorized Question.

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Re: How do I convert a very long bit string into a number?
by jdporter (Paladin) on Jan 15, 2009 at 21:46 UTC
    Combine unpack with Math::BigInt:
    use Math::BigInt; use bigint; use strict; use warnings; sub convert_bitstring_to_number { my $bitstring = shift; my $h = unpack( 'H*', $bitstring ); my $bh = new Math::BigInt '0x'.$h; $bh->as_int; }

      This can be generalised for other orderings of the bytes, and of the bits in each byte, of the bitstring. Four types of bitstring can be identified:

      1. big-endian: ms-bit of first byte is the ms-bit of the multi-byte number. This is handled as shown, ie:

        my $h = unpack( 'H*', $bitstring ) ;

      2. little-endian: ls-bit of first byte is the ls-bit of the multi-byte number. This is handled:

        my $h = unpack( 'H*', scalar reverse $bitstring ) ;
        Note that this is the same order as vec($v, $b, 1)

      3. big-endian reversed bytes: ls-bit of first byte is the ms-bit of the multi-byte number. This is handled:

        my $h = unpack( 'H*', pack('b*', unpack('B*', $bitstring)) ) ;

      4. little-endian reversed bytes: ms-bit of first byte is the ls-bit of the multi-byte number. This is handled:

        my $h = unpack( 'H*', pack('b*', unpack('B*', scalar reverse $bitstr +ing)) ) ;

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