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Re^3: How can POE use a hash reference like a hash?by rcaputo (Chaplain) |
on Dec 27, 2008 at 15:48 UTC ( [id://732810]=note: print w/replies, xml ) | Need Help?? |
That node seems to agree with me: Arrows are optional between two subscripts. In $x->[0]->[1], $x is not a subscript but both [0] and [1] are. We may remove the second arrow without changing the expression, giving $x->[0][1]. The arrow between $x and [0] isn't between two subscripts, however, so it is required to maintain equivalence with the original expression.
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