Alright, I also expected a return of 1,2,3,4, and 5 as the values printed out. However, I think I have learned where I went wrong. I just wanted to make sure I understood the last paragraph of HOW THE CODE WORKS.
If I understand this correctly, the $each variable actually acts as a reference to the current place in the array that the foreach loop is currently at. So in effect we are actually altering the first array with the $each *= 2; and then simply setting the $i place in the @newlist to be the same value. This is the reason why we are subtracting, in the last loop, the exact same values from each other.
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Re: Re: Re: NEWBIE Brain Teaser
by nysus (Parson) on Apr 15, 2001 at 08:27 UTC