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Re: Challenge: Simple algorithm for continuing series of integers

by kyle (Abbot)
on Oct 20, 2008 at 19:09 UTC ( [id://718277]=note: print w/replies, xml ) Need Help??

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  1. or download this
    sub geometric {
    my @known = @_;
...
    return undef if scalar @next != 1;
    return $next[0];
}

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