If on the other hand you're talking about querying the subversion server, then you can get the info with a subversion command such as svn list -R. For example:

my $repos = q{svn://.../trunk};
my $svn = q{/usr/local/bin/svn};
my $tree = qx{$svn list -R $repos};
print $tree;
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Sorry for the delay. I modified code that I found but get out of memory errors after six or so file names are listed. I see in the File::Slurp documentation that there's a way to read just filenames (and not the entire file contents as I believe that I'm doing below), but am not sure what to do with the following to just read the filenames.

#!/usr/bin/perl

use strict;
use warnings;

use File::Slurp;
use File::Find;

my $dir="C:\\Documents and Settings\\Administrator\\Desktop\\SVN\\trun
+k";

# read an entire file into a scalar (a.k.a. 'slurping')

find( \&show_subdirectories, $dir);

sub show_subdirectories{

    if ( -d ) {

        if ( $_ eq '.svn' ) {
            # don't traverse into subversion related directories
            $File::Find::prune = 1;
            return;
        }
        # for directories, only print path
        my $filepath ="$File::Find::name";
        return;
    }

    -f        or return;  # if not a file
     /\.(xls|mdb)$/ or return;  # if not the right extension

    my $perl = read_file( $_ );
    my $filepath="$File::Find::name";
    my @filearray=split(/\\trunk\//,$filepath);
    my $fileElt = $filearray[1];
 
    print "FILEARRAY is $fileElt and FILE is $_\n";
}
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This line is reading in the file contents:

   my $perl = read_file( $_ );
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If you don't want to read the file contents, then just remove that line.