check for directory no mather what case (linux)

Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:

Hi, I want to check if a directoy name exists.
/somedir/directory

For example want to check if "directoy", "Directory", "diRECtory" or "direCTORY" ....... exists
It's so i wont create the "directory" if "DiRectorY" already exists.

mkpath($filepath) unless -d "$filepath" ;
[download]

Will only be true on same-case directory's
Is there someway i can check it like a regex =~ /directory/i i can use "find" to create a dir list and check if it exists, but i thought that there might be a cleaner/easier way.
Thanks,
Milo

Comment on check for directory no mather what case (linux) Download Code

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Re: check for directory no mather what case (linux) by andyford (Curate) on Oct 19, 2007 at 19:22 UTC
Just switch to an OS that has a non-case sensitive file system. Seriously though, you've got the idea, just look up the readdir function (perldoc -f readdir might work for you or try readdir) and you'll have what you need. non-Perl: Andy Ford	[reply]
Re: check for directory no mather what case (linux) by tuxz0r (Pilgrim) on Oct 19, 2007 at 20:16 UTC
Just toying around with the possibilites, I don't think you necessarily need opendir or readdir. Using glob() might do the trick, as long as you can get the base (root) of the directory you're checking for, for example: `$dir = "/home/Bob/XXX"; $dir =~ m/(\/.)\/([^\/]+)\/?$/ and ($base,$dirname) = ($1,$2); mkdir $dir unless scalar grep(m/$dirname/i, glob("$base/"));` [download] Caveat, depending on the platform the slashes might trip you up (forward or backward), but in general it seems to work when I test it out on my Linux and AIX machines just fine. NOTE: Correction, I had pasted the code from the wrong test script - correct code above now	[reply] [d/l]


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