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Re^2: Using & in function calls (&foo != foo(@_))by lodin (Hermit) |
on Sep 29, 2007 at 16:08 UTC ( [id://641702]=note: print w/replies, xml ) | Need Help?? |
It passes the current @_ to the function called. This is probably just a matter of wording, but I'd say it's sharing @_. &foo and foo(@_) are not equivalent. An example:
lodin
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