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Re^3: Arbitrary number of captures in a regular expression

by Sidhekin (Priest)
on Sep 25, 2007 at 11:06 UTC ( #640897=note: print w/replies, xml ) Need Help??

in reply to Re^2: Arbitrary number of captures in a regular expression
in thread Arbitrary number of captures in a regular expression

Id do something like this myself. Except id probably not use look ahead and instead would approach it a different way.

I was annoyed with the lookahead myself, but it's unlikely to be a big deal, and I could not at the time see any way to avoid it. After some thinking, however, I believe I see a way to avoid looking ahead more than once -- just include it in the first alternation, which is matched precisely once on a successful match (anchored to the beginning of the string, and the only alternation that can match there):

my (@match) = $str =~ /(?:^foo (?=(?:m \d+ )+bar)|(?<!^)\G)m (\d+) /g;

... or, in the less-terse form:

my (@match) = $str =~ / (?: ^foo\ (?= (?:m\ \d+\ )+bar) # overall match from ^foo | (?<!^) \G # or continue from not-^ ) m\ (\d+)\ # grab each digit sequence /xg;

I think that's the best I got. Match that? :)

print "Just another Perl ${\(trickster and hacker)},"
The Sidhekin proves Sidhe did it!

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Re^4: Arbitrary number of captures in a regular expression
by demerphq (Chancellor) on Sep 25, 2007 at 16:12 UTC

    I dont have time to put together a working example, but what i had in mind was using while, \G and also the /gc modifier in scalar context. Maybe from that you can come up with a working example, or prove me wrong, before I get the time to do anything useful with it.

    Using the underused /gc modifier was the key point I was thinking of tho.

    Oh and to be clear I wasnt trying to say my way would be better, just different. :-)


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