Re^5: eval order of args to a sub


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Re^5: eval order of args to a sub

by TGI (Parson)

on May 31, 2007 at 00:29 UTC ( [id://618364]=note: print w/replies, xml )

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in reply to Re^4: eval order of args to a sub
in thread eval order of args to a sub

Absolutely, the post-*crement operators MUST create an anonymous value, so they do.

I wonder though, what the "expected" or "natural" behavior of the other constructs I posted should be.

Construct  Behavior  Expected
$i += 2    \$i       ???
$i++       Anon.     Anon.
$i + 1     Anon.     Anon.
$i++       Anon.     Anon.
++$i       \$i       Anon.
$i=2       \$i       ???
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From reading the other posts here, I feel comfortable saying that people expect ++$i to pass an anonymous value. I'm not 100% sure what I'd expect the assignment operators (=, *=, etc) to pass. Since most langauges pass by value, I guess I'd expect the assignment operators to pass anonymous values equal to the value assigned to $i. For example for foo($i=2) my faulty intuition is that foo() would get an anonymous 2 in $_[0].

TGI says moo