This is my entry on
FizzBuzz:
print+(Fizz)[$_%3].(Buzz)[$_%5]||$_,$/for 1..100
or in words: since for any
n multiple of 3
n % 3 == 0 I just make a list which has Fizz at index 0 and nothing else in it, and pull the (n%3)
th element out of that list. Same for 5. Then I concatenate them together, print the result of that if it's true (not empty string), otherwise just
n; then the default input record separator. Repeat for 1 to 100.
Straight forward and (almost) readable code (just add whitespace :-)
--shmem
_($_=" "x(1<<5)."?\n".q·/)Oo. G°\ /
/\_¯/(q /
---------------------------- \__(m.====·.(_("always off the crowd"))."·
");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}
