(OT) Fibonacci numbers in Ruby - final shot

#!/usr/bin/env ruby
x=i=1;p x+=i=x-i while+1
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2006-11-17 Retitled by Arunbear, as per Monastery guidelines
Original title: 'Fibonacci numbers - final shot - 24 chars'

Comment on (OT) Fibonacci numbers in Ruby - final shot - 24 chars Download Code

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Re: (OT) Fibonacci numbers in Ruby - final shot - 24 chars by ambrus (Abbot) on Nov 15, 2006 at 07:20 UTC
Meh, if you don't have to use perl, you can do much better: Re: Fibonacci numbers (again). Update: let's put them under each other to see which one is longer. `1 2 3 123456789012345678901234567890123 dc -e1d[pdsd+ldrlxx]dsxx ruby -e'x=i=1;p x+=i=x-i while+1'` [download]	[reply] [d/l]
Re: (OT) Fibonacci numbers in Ruby - final shot - 24 chars by ambrus (Abbot) on Nov 15, 2006 at 09:24 UTC
It's also easy to shorten the ruby version by two characters `x=i=1;loop{p x+=i=x-i}` [download]	[reply] [d/l]
Re: (OT) Fibonacci numbers in Ruby - final shot - 24 chars by ikegami (Patriarch) on Nov 15, 2006 at 02:14 UTC
That's 33, not 24 (since omitting the first line gives a compile error). If you want really small, try 4! `do f` [download] I'm sure `f` can be made way smaller than `ruby`. Update: Downsized from 10	[reply] [d/l] [select]
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