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Re^2: testing number of occurrences in a word

by grinder (Bishop)
on Sep 19, 2006 at 15:05 UTC ( [id://573746]=note: print w/replies, xml ) Need Help??


in reply to Re: testing number of occurrences in a word
in thread testing number of occurrences in a word

49, but then again I suck at golf.

sub isogram { #234567890#234567890#234567890#234567890#234567890 my%h=map{($_,1)}split//,$_[0];keys%h==length$_[0] } print "$_ is ", (isogram($_) ? '' : 'not '), "an isogram\n" for @ARGV;

Duh, johngg had the right idea, except he wasn't greedy enough (nor was I. What's with the $_[0]? Sheesh.):

sub isogram { #23456789 /(.).*\1/ } print "$_ is ", (isogram() ? '' : 'not '), "an isogram\n" for @ARGV;

That makes for 9.

• another intruder with the mooring in the heart of the Perl

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Re^3: testing number of occurrences in a word
by liverpole (Monsignor) on Sep 19, 2006 at 16:58 UTC
    Very nice, but your logic is reversed.  Remember, an isogram does NOT have any letters duplicated.

    To keep it golfed, either change the caller of the subroutine:

    print "$_ is ", (isogram() ? 'not ' : ''), "an isogram\n" for @ARGV;

    or, better yet, the subroutine name:

    sub not_isogram { # ... } print "$_ is ", (not_isogram() ? '': 'not '), "an isogram\n" for @ARGV +;

    s''(q.S:$/9=(T1';s;(..)(..);$..=substr+crypt($1,$2),2,3;eg;print$..$/

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