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Re^4: Obtaining terms in an expansion

by pKai (Priest)
on Jan 06, 2006 at 19:34 UTC ( [id://521606]=note: print w/replies, xml ) Need Help??


in reply to Re^3: Obtaining terms in an expansion
in thread Obtaining terms in an expansion

Thank you, for pointing me to the "factorial"
Note to self: Don't transfer mathematical/technical terms from German to English without consulting a dictionary first.

Also, would you be able to give example code for the subset iteration with Math::Combinatorics?

If there is an easy way to do so, it has escaped me.

The closest I saw in the docs was that example to generate:
"Morse signals: diferent signals of 3 positions using the two symbols - and .".

Now Morse signals of length 3 are surely one-to-one and onto the subsets of a 3 element set (set elements = pos in signal; element not/contained = dot/dash)

The given iteration using next_multiset and next_string is like computing 2**n as sumk=0..n nCk

At least this is not trivial application of the modules methods.

Replies are listed 'Best First'.
Re^5: Obtaining terms in an expansion
by ivancho (Hermit) on Jan 06, 2006 at 22:19 UTC
    I guess that's as good as it gets from Math::Combinatorics - doable, but not very natural.

    There are plenty of other iterators out there that give all the subsets, though - List::PowerSet, Data::PowerSet, Algorithm::ChooseSubsets - We just have to convert them to give a bit mask instead - ie:

    use List::PowerSet qw/powerset_lazy/; my @set = (0) x $N; my @C = (1) x 2**$N; my $M = 0; my $ps_itr = powerset_lazy(0 .. $N-1); while (my $ref_set = $ps_itr->()) { $_ = 1 for local @set[@$ref_set]; $C[ $M ] *= $arr->[ $_ ][ $set[$_] ] for 0 .. $N-1; $M++; }
Re^5: Obtaining terms in an expansion
by DungeonKeeper (Novice) on Jan 09, 2006 at 10:09 UTC
    The 2**N doesn't need to be computed anyway. next_multiset() will just keep returning each possible set until all have been returned, at which point it returns undef().

    Everything but the troll

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