Re: perl numeric expressions

If you use eq instead of == it yields the correct result :

#!/usr/bin/perl

use strict;
use warnings;

my $x1 = 44.7;
my $x2 = 44.9-0.2;

print "numbers $x1 $x2 - ";
if ($x1 eq $x2) {
 print "SAME\n";
} else {
 print "NOT SAME\n";
}
[download]

.. but I'm not sure as why it is so !?

Comment on Re: perl numeric expressions Select or Download Code

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Re^2: perl numeric expressions by tphyahoo (Vicar) on Nov 28, 2005 at 13:35 UTC
it's because "eq" compares strings, not numbers.	[reply]
Re^3: perl numeric expressions by secret (Beadle) on Nov 28, 2005 at 13:40 UTC
So it means that internally doing `eq` on a "number" is like doing the appropriate sprintf and `==` and that's how "extrapolation" of a number into a string works ?	[reply] [d/l] [select]
Re^4: perl numeric expressions by tphyahoo (Vicar) on Nov 28, 2005 at 14:39 UTC
not really sure of the gory details. But I think the term you want if you're going to be googling around for more info could be "stringification". The opposite would be "nummification." UPDATE: But you better double check that. These may be perl 6 only terms. (And it was just a guess.)	[reply]


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