|No such thing as a small change|
do, local and a qualified identifier?by tomazos (Deacon)
|on Oct 09, 2005 at 01:11 UTC||Need Help??|
tomazos has asked for the wisdom of the Perl Monks concerning the following question:
I have been handed a Perl script to work with that has a configuration file specified by a command-line argument.
The configuration file is selected based on the command-line parameter and then loaded with a do $config_filename in the main script.
In a given configuration file it says something along the lines of:
Later on init gets called from the main script.
After that, what is the value of $Foo::bar in the main script and why?
What is the purpose of the declaring $Foo::bar local? I thought it gave it a global symbol a local value?
If so, when init is called will it set the localized value like a closure or the global value?
Further, what is the point of qualifying the identifier with the package name? and does that have any effect on the functionality?
Totally confused. Have not seen this way to do it before.
Update: Yes, we were getting the "$bar used only once" error when I changed it to use our and unqualified - even though bar is mentioned outside of the do. This is what confused me. Why do you get that error for an our and not for a local? I don't see it changing the number of times it is mentioned. (In fact, couldn't perl warn "useless use of local" in the above code, as the local does absolutely nothing.)