You can do that using the /e modifier:
$a = "size=1111";
$a =~ s/(\d+)/($1 > 5) ? 5 : $1/e;
print $a, "\n"
Igor S. Lopes - izut
surrender to perl. your code, your rules.
| [reply] [d/l] [select] |
$message =~ s~\[size=(.+?)\](.+?)\[/size\]~($1 > 5) ? "<font size=\"5\
+">$2</font>" : "<font size=\"$1\">$2</font>"~eisg;
| [reply] [d/l] |
I think this way is easier to read:
message =~ s~\[size=(.+?)\](.+?)\[/size\]~"<font size=\"".(($1 > 5) ?
+5 : $1)."\>$2</font>"~eisg;
Igor S. Lopes - izut
surrender to perl. your code, your rules.
| [reply] [d/l] |
You're already using the /e modifier. Thus you can put into the replacement portion of the s/// operator "any" perl code. No reason why a ternary operator could not be there... | [reply] [d/l] [select] |
At worst, another way with the ternary (or "conditional") operator:
use vars qw ( $message);
$message = qq ( Foo bar <font size="7"> phrase here </font> blivits. )
+;
$message =~ s#(\d+)#($1 > 5) ? 5 : $1#eisg;
if ( $1 ) {
print "\n After s###, \$1 is: $1 \n ...and revised \$msg is:
+$message \n";
}
else
{
print "\n no \$1 found \n";
}
and output is:
After s###, $1 is: 7
...and revised $message is: Foo bar <font size="5"> phrase here </font> blivits.
- the $message html fragment is well-formatted... for 4.0, but display elements are now better (well, that's what the experts say) done with css
- the "sig" regex modifiers are not needed with this $message but might well be with more typical .html
- and, while matching on <font size=" before the 7> is omitted only to keep the example simple (and is easy enough to add), this is a very limited and profoundly un-extensible method -- better to use an html parser, as suggested elsewhere. For example, a web'ster using <font... may well have multiple and/or variant forms of elements in a single font tag, as, for example,
<font color="red" size=+1...>
- and, finally, despite generous efforts by OP, I can't see how Re^2 or Re^3 can or do work ... even with "<"s replacing "["s
...so would welcome education.
| [reply] [d/l] |