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Re^4: Shortcut operator for $a->{'b'}=$b if $b;by leriksen (Curate) |
on Sep 21, 2005 at 03:24 UTC ( [id://493648]=note: print w/replies, xml ) | Need Help?? |
Maybe someone can suggest how to define a '?=' operator $a->{'b'} ?= $b; assigns $b to $a->{'b'} if $b is defined, does not autovivify $a->{'b'} if $b not defined is that possible? - I'm thinking of use overload but I dimly recall that there is a finite set of operators you can overload and ?= isnt one of them. ...reality must take precedence over public relations, for nature cannot be fooled. - R P Feynmann
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