Take out date part of my field value

Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:

I am trying to check if a field value has a date in the first part of the value and if it does then delete that part of the value:

(08/04/05) Information here etc...
[download]

To look like this:

Information here etc...
[download]

My attempt is not working. Please advise.

if($field =~ /d2\/d2\/d2/)
{ 
    s/1//;
}
[download]

Comment on Take out date part of my field value Select or Download Code

Replies are listed 'Best First'.
Re: Take out date part of my field value by socketdave (Curate) on Aug 24, 2005 at 14:45 UTC
`$field =~ s/$\d{2}\/\d{2}\/\d{2}$//;` This will strip out the parentheses and the date. You were on the right track, but regex quantifiers (other than *, + and ?) use {}. Hope this helps.	[reply] [d/l]
Re^2: Take out date part of my field value by derby (Abbot) on Aug 24, 2005 at 14:54 UTC
++ the only thing I would change is the delimitter ... then no need to escape the slash. `$field =~ s#$\d{2}/\d{2}/\d{2}$##;` [download] -derby	[reply] [d/l]
Re: Take out date part of my field value by pbeckingham (Parson) on Aug 24, 2005 at 14:41 UTC
Simply substitute nothing for a pattern that matches your date. You may need to modify the pattern, and you probably should check out some of the excellent pages on regular expressions. `$field =~ s/^$\d\d\/\d\d\/\d\d$\s+//;` [download] pbeckingham - typist, perishable vertebrate.	[reply] [d/l]
Re: Take out date part of my field value by davidrw (Prior) on Aug 24, 2005 at 14:53 UTC
slight variation the above for legibility (avoids having to escape the slashes): `$field =~ s#^$\d{2}/\d{2}/\d{2}$\s+##;` [download]	[reply] [d/l]
Re: Take out date part of my field value by punkish (Priest) on Aug 24, 2005 at 17:03 UTC
`d2 # matches the letter 'd' followed by the number '2' # not what you want d{2} # matches the letter 'd' at least and at most 2 times # this is what you want s/1//; # replaces the number '1' with nothing # not what you want s/$1// # does what you want` [download] -- when small people start casting long shadows, it is time to go to bed	[reply] [d/l]
Re: Take out date part of my field value by sapnac (Beadle) on Aug 24, 2005 at 20:29 UTC
`Try this; $field =~ s/\d+\/\d+\/\d+//g; Hope it helps!` [download]	[reply] [d/l]


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