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Re^4: How will you use state declared variables in Perl6?

by BrowserUk (Patriarch)
on Jul 08, 2005 at 23:12 UTC ( [id://473607]=note: print w/replies, xml ) Need Help??


in reply to Re^3: How will you use state declared variables in Perl6?
in thread How will you use state declared variables in Perl6?

Okay. The analogy with C statics was flawed. That makes sense.

I should really have referred to our rather than local, but I think your explaination suffices.

What happens if I do: 

sub bar {
    state $foo;
    ...
    my $code = sub qux {
        state $foo;
    };
    ...
}

[download]
  • Is this illegal?
  • Or do the two refer to the same thing?
  • Or does the inner $foo hide the outer $foo for the duration of that scope?
    Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
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    • Replies are listed 'Best First'.
    Re^5: How will you use state declared variables in Perl6?
    by TimToady (Parson) on Jul 08, 2005 at 23:27 UTC
      If it's illegal, it's because you took the address of a named declaration, not because of the state declarations. But ignoring the "qux" (and the entire question of whether that should be legal) your use of state variables would certainly be legal. The inner $foo hides the outer $foo just as a "my" variable would. And every time you clone the inner closure you'll get a new copy of the inner state variable, and it will initialize itself the first time that clone is called. It implies the existence of some kind of persistent lexical pad, which is a certain amount of work for the implementation, but we really didn't see much benefit in duplicating the functionality of globals, and a lot of benefit in having a kind of "my" that doesn't reinitialize the second time through.
    		[reply]

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