The error could also mean that there isn't an array '@s340Strings' in your code.

You may have typo'd the name of the array, or it may be a subset of that... if you wanted to print the array '@s' and then immediately the string literal '340Strings' (which would probably be bad, as it'll likely look like part of the last item in the array), you could do:

If you're just trying to print the literal string '@s340Strings', then either switch to single quotes, so it won't try to do variable expansion on you, or escape the @ with a \, as the error message suggested.

Where do you define the array and assign to it because print "@s340Strings"; should work. Though if you want the contents of an array (an @array used in $scalar location will print the length of the array) then you want a for/foreach statement - like print for @s340Strings;

Update: Interesting I've never run into that before, that actually would help quite a bit. Thanks!

Putting an array in double quotes does not impose scalar context on the array; it does an implicit call to join using $" (default is a space) as the separator. Without the double quotes, print would print the contents using $, (default is empty string) as a separator.

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Caution: Contents may have been coded under pressure.

an @array used in $scalar location will print the length of the array

True, but this isn't the case.

perl -le '@A=qw(a b c d); print "@A"'
a b c d
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!#/path/to/perl

use Data::Dumper;

print Dumper(@s340Strings);

exit;
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my @s340Strings = qw("abc", "cdef","yxx","zzz");

print "@s340Strings\n";

prints:
"abc", "cdef","yxx","zzz"
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That code is correct, but very confusing. You create a two element array, $s340Strings[0] == "\"abc\"," and $s340Strings[1] == "\"cdef\",\"yxx\",\"zzz\"". That may be what you intended, but when I read it, it looks like you intend:

my @s340Strings = qw(abc cdef yxx zzz);
# or
my @s340Strings = ("abc","cdef","yxx","zzz");
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Just trying to clarify...

    -Bryan