Re^4: Array of hashes reference problem

Thanks for the help. Okay. This time, I'm SURE I've got all the pieces, because I ran this as a separate Perl program. And, I get the following error when I run it:

Can't use string ("") as a HASH ref while "strict refs" in use at test-hash.pl line 19

Line 19 contains $arrayAoH$j{$key} = $value;

Thoughts?

Thanks! tl

#!/usr/bin/perl -w
use strict;
my @arrayAoH = "";
my $out = "First one:  one
Second one: second";

    my @discovered = split /\n/, $out;
    my $i = 0; # i holds the line number of the input (@discovered) ar
+ray.
    my $j = 0; # j holds the number of the table row.
   my $key;
   my $value;
# $# returns the subscript of the last element in the array.
    until ($i eq $#discovered){
        if ($discovered[$i] =~ m/First one:/){
# parse this line containing labels and values until a blank line is f
+ound
            until ($discovered[$i] eq ""){
                ($key, $value) = split /:\s*/, $discovered[$i];
##            $arrayAoH[$j] = { $key => $value };
                $arrayAoH[$j]{$key} = $value;
                $i++;
            }
            $j++;
        }
        else {
        $i++;}
    }
[download]

Comment on Re^4: Array of hashes reference problem Download Code

Replies are listed 'Best First'.
Re^5: Array of hashes reference problem by sapnac (Beadle) on Jun 22, 2005 at 20:32 UTC
Check this code; The code posted goes in an infinite loop. `#!/usr/bin/perl -w use strict; my @arrayAoH; my $out = "First one: one Second one: second"; my ( $i,$j ); my ($key,$value); my @discovered = split /\n/, $out; $i = 0; # i holds the line number of the input (@discovered) array. $j = 0; # j holds the number of the table row. until ($i > $#discovered){ ($key, $value) = split /:\s*/, $discovered[$i]; $arrayAoH[$j]{$key} = $value; $i++; }` [download] Hope it helps! Good Luck!	[reply] [d/l]
Re^6: Array of hashes reference problem by tlemons (Novice) on Jun 22, 2005 at 21:30 UTC
Thanks very much! It solved my problem. Aside from the infinite loop, your code worked and my didn't. I stared at it, and noticed that the important difference was: Your code my @arrayAoH; My code my @arrayAoH = ""; By initializing the array, I shot myself in the foot. When I removed that "" initialization, my code worked great. Thanks VERY much for the help! tl	[reply]
Re^5: Array of hashes reference problem by djohnston (Monk) on Jun 22, 2005 at 20:29 UTC
You could try `($arrayAoH[$j]\|\|={})->{$key} = $value;` which should get you past that warning, but I suspect you will encounter other issues. I also suspect that there might be a much simpler algorithm to get done whatever it is you're attempting to do. Perhaps it'd be best if you post more sample data along with a detailed description of the data structure you're trying to build out of it.	[reply] [d/l]


Welcome to the Monastery
	PerlMonks