There's a better solution here. Always use warnings, especially use warnings 'void';, which will give you a "useless use of a constant" warning, since your "\n" isn't doing anything...
(OK, looking at the output, this is one of the few cases where you get a useful "'print (' interpreted as function" without getting some other error... but the advice still holds. Use warings, or -w, even on quick one-liner check code, esp when something strange is happening.)
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