in reply to Re: increment # but keep # of digits same
in thread increment # but keep # of digits same
That could simply be:
#!/usr/bin/perl foreach("00001".."00021"){ print "$_\n"; }
Edit: Just showing that the increment operator is a bit magical, but now I see I've probably missed the point a bit.
-Any sufficiently advanced technology is
indistinguishable from doubletalk.
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