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Re^3: finding matches in the same arrayby polettix (Vicar) |
on Apr 13, 2005 at 18:19 UTC ( [id://447547]=note: print w/replies, xml ) | Need Help?? |
This does not seem to be an average :) First item is divided by 1, second divided by 2, third by 3... - maybe it's better to make the division at the end:
Flavio (perl -e "print(scalar(reverse('ti.xittelop@oivalf')))") Don't fool yourself.
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