I.e. can you break the name of the scalar up and insert a number into it $Sel[1......80]Ttl so i can then use that in my additions.. ?

Yes, but the best way to do almost that it is to use an array:

for my $number (1 .. 80) {
 $selTtl[$number] = $value;
}
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Really, the advantages of not having to type 2 more characters ([]) are not worth it, considering the potential problems.