Re: Equivalency of Code

They are quite clearly not the same.

$x = 3;
print $x++;
[download]

$x = 3;
print $x += 1;
[download]

Those two are only the same as regards their effect on $x. The expressions do not *evaluate* to be the same.

Comment on Re: Equivalency of Code Select or Download Code

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Re^2: Equivalency of Code by adamk (Chaplain) on Feb 08, 2005 at 03:10 UTC
No fair! HIS code didn't have print statements in it, he was using them as standalone statements. You are testing something different. `$x = 3; $x++; print $x;` [download] vs `$x = 3; $x += 1; print $x;` [download] ...would be more accurate. Of course, given problems with operator overloading, they stil arn't actually equal.	[reply] [d/l] [select]
Re^3: Equivalency of Code by DrHyde (Prior) on Feb 08, 2005 at 10:39 UTC
The point is that `$x++` and `$x += 1` don't just fiddle with the value of `$x`. Those statements also have values themselves. If a bit of code is to be equivalent to another, then it needs to both have the same side-effects and the same value as the other does. I try not to think about operator overloading or tieing :-)	[reply] [d/l] [select]
Re^4: Equivalency of Code by Anonymous Monk on Feb 08, 2005 at 10:57 UTC
The statements are presented where in void context - and in void context, there's no return value.	[reply]


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