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Re^2: getting the highest value in a simpler way

by uksza (Canon)
on Dec 19, 2004 at 02:31 UTC ( #415930=note: print w/replies, xml ) Need Help??

in reply to Re: getting the highest value in a simpler way
in thread getting the highest value in a simpler way


$highestvalue = [ $x => $y ] -> [ $x <= $y ]
Anybody can explanin me this code? I'm a bit confused ;-)


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Re^3: getting the highest value in a simpler way
by BrowserUk (Pope) on Dec 19, 2004 at 03:07 UTC

    [ $x => $y ] is the same as [ $x, $y ] which is the essentially the same as

    my $ary = ( $x, $y ); my $aryRef = \ @ary;

    And $x <= $y is just a boolean expression that will give a false (0) result if $x > $y and true value (1) otherwise.

    $aryRef->[ 0/1 ] will return either $ary[ 0 ] or $ary[ 1 ].

    Putting it all together, you get an expression that will construct an anonymous array containing $x, $y, then dereferences that anonmous array and uses the boolean result of the comparison to select the greater of the two values before assigning it to the scalar.

    Examine what is said, not who speaks.        The end of an era!
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    "Think for yourself!" - Abigail        "Time is a poor substitute for thought"--theorbtwo         "Efficiency is intelligent laziness." -David Dunham
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      I understand!! ;-)
      So, in exmaple:
      my $x = 5 my $y = 10 my $highestvalue = [ $x => $y ] -> [ $x <= $y ] #we have @aray(5,10) and because (5 <= 10) it returns 1, so $highestvalue = aray[1] thats mean 10 in this example, right?

      Eh, nice trick... ;-)
      Thanks for you reply.

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