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Re^5: Private Methods Meditationby Ovid (Cardinal) |
on Jul 19, 2004 at 20:59 UTC ( [id://375695]=note: print w/replies, xml ) | Need Help?? |
If you have a method in your subclass, you always run the risk that the parent class will define a method with the same name, but with very different functionality. Not so. In C++, a method must be explicitly declared as virtual if you wish to allow it to be overridden in subclasses. As a result, a if you call a superclass method and that method calls the method foo(), it will only grab the subclass foo() if the superclass had declared foo() as virtual. (At least, that's my understanding. C++ is not my strong suit.) In Java, you can declare a method as private and subclasses cannot override that method. I'm still not sure how subclassing messes with something's internals, though. In Perl, it's pretty much a given that this will happen since there is so little support for encapsulation. This ties in with my comments above. I don't know if tilly meant all OO languages. Cheers, New address of my CGI Course.
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